Finding values in an Array

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Aldo Amaya
Aldo Amaya on 30 Jan 2014
Commented: Aldo Amaya on 30 Jan 2014
If I have an array such as
Subject= [126;156;1992, 203, 186] % First two digits determine group, additional numbers are specific subject within that group.
Is there a method to only read the first two values of each row in order to determine what group the subject is?
Group= [12;15;19;20;18] %%%This is what I would like the result to be.

Accepted Answer

Jos (10584)
Jos (10584) on 30 Jan 2014
Apply some arithmetic:
Subject = [126 156 1992 203 186 10 100 100000]
Group = fix(Subject ./ (10.^floor(log10(Subject)-1)))

More Answers (2)

Walter Roberson
Walter Roberson on 30 Jan 2014
Group = floor(Subject ./ 10);
  1 Comment
Aldo Amaya
Aldo Amaya on 30 Jan 2014
Thanks for the reply, the only issue is that they are not all the same number of elements. Subjects elements range from 3-5 currently.

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Aldo Amaya
Aldo Amaya on 30 Jan 2014
Edited: Aldo Amaya on 30 Jan 2014
This was my solution but I wish there was a cleaner way to do it
Group = floor(Namex2 ./ 10);
i=1;
while i<=length(Group)
if Group(i)>=100
Group(i)=floor(Group(i)./ 10);
else
end
i=i+1;
end

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