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can you help me to ploting the number of operations and time of execution

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function pgdA
n=1000;
i=45;
while mod(n, i)~=0;
i=i-1;
end
flops mod(n,i);
plot mod(n,i);
  3 Comments
Walter Roberson
Walter Roberson on 21 Jan 2014
"flops" is "floating point operations per second". There was a time when it had meaning in computers, but it does not have much meaning now.
Walter Roberson
Walter Roberson on 21 Jan 2014
As I have indicated in multiple posts, "flops", floating point operations per second, is not meaningful in modern computers, and there is no way to calculate it now.
If, though, you wanted to count "actions" like you did in http://www.mathworks.co.uk/matlabcentral/answers/105512-plotting-the-number-of-actions-for-ex-i-i-1-action-pgd-n-i-action-pgd-n-action then we might be able to help you, provided that you indicate all the different "actions" that you want to be counted individually.
Please note that your code has nothing to do with finding "mod", and is instead an algorithm for finding the greatest divisor of "n" that is at most "i"; with those particular values it would be 25 that would be left for "i"

Answers (1)

Paul
Paul on 21 Jan 2014
Do you mean something like this:
n=10000;
i=47;
j=0;
while mod(n, i)~=0;
if(j==0)
tic
end
i=i-1;
j=j+1;
t(j)=toc;
tic
end
j=1:j;
plot(j,t),xlabel('iteration number'),ylabel('time [s]');

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