How to delete cell entries with an index vector

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Melanie
Melanie on 10 Jan 2014
Commented: Simon on 13 Jan 2014
Dear community,
I have a cell
A=cell(m,n)
and a logical vector
b=(m,1)
containing logical ones and zeros (true, false). What I like to do now is to delete the cell entries, if there is a logical one
A(b,:)=[];
But the error is: Index of element to remove exceeds matrix dimensions. What have I done wrong?
Thanks a lot!

Answers (3)

Azzi Abdelmalek
Azzi Abdelmalek on 10 Jan 2014
n=3;
m=6;
A=num2cell(rand(m,n))
idx=[1 0 0 1 1 0]
A(logical(idx),:)=[]

Simon
Simon on 10 Jan 2014
Hi!
Are you sure that b is not longer than size(1) of A? Is b really a logical vector with true or false? I have no problem if I use
n=3
m=5
A=cell(m,n)
b=false(m,1)
b(2) = true
b(5) = true
A(b,:)=[]
An error is thrown for
A=cell(m,n)
b(6) = true
A(b,:)=[]

Melanie
Melanie on 13 Jan 2014
Thanks for your answers, I still have the error code:
Index of element to remove exceeds
matrix dimensions.
I checked the sizes now for 100 times :D I don't know what could help me, m is always the same.
BR, MS
  1 Comment
Simon
Simon on 13 Jan 2014
I'm wondering where your error message comes from. If I use my example above the message is
Matrix index is out of range for deletion.
Tested on Matlab R2010b. Maybe we use different versions or the problem is different ...

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